2 SO2(g) + O2(g) + 2 H2O(ℓ) −→ 2 H2SO4(ℓ) What mass in grams of SO2 is needed to
react with 1527 g of O2?

6116g

Explanation:

2SO2(g) + O2(g) + 2H2O(ℓ) −→ 2H2SO4(ℓ)

We want to find the mass in grams of SO2 that is needed to react with 1527 g of O2. First we must convert the grams of O2 to moles of O2 then to moles of SO2 and then to grams of SO2

So first lets find the molar mass of O2

The mass of oxygen according to a periodic table is 15.999

Using this the mass of O2 would be 15.999(2) = 31.988g

Next we need to identify the mole ratio of O2 to SO2

Looking at the equation for 1 mole of O2 there are two moles of SO2

Next we need to find the molar mass of SO2

Again the mass of oxygen is 15.999g and the mass of Sulfur is 32.066

So the mass of SO2 would be 15.999(2) + 32.066 = 64.064g

Now that we have found all the needed conversions :

We can now use dimensional analysis to calculate the answer.

Kindly check the attached image to see the table. ( sorry if its a bit blurry )
Explanation : The conversions are used to cancel out the units to get to the final unit which is gSO2.

Once the units are cancelled out except for the gSO2 we mutliply and divide based off of what the table says to do.
Here first we divide 1527 by 31.988. We than multiply by 2. Finally we multiply by 64.064 to get the final answer which is 6116gSO2

Answer:

Step-by-step explanation:

The input force is 50 N. But it will not create not any change. No mechanical advantage is observed.

Answer:

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 ×328 K

Solving:

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.