18.01.2022

Electron Configuration Worksheet

This entire assignment using the Fictional Periodic Table.

Draw the Arrow (Orbital) Diagram for the following elements (You MUST label the energy levels and sub-levels)

Poopium


Grapium


Noobon


Supermanium


Bolonium


Write the unabbreviated (extended) electron configurations of the following elements:

Soulsteel________________________________________________
Coyotium ________________________________________________
Jellium ________________________________________________
Bendezium ________________________________________________
Uridium________________________________________________
Write the abbreviated (noble gas) electron configurations of the following elements:
Internium ________________________________________________
Calculon ________________________________________________
Dexton ________________________________________________
Chronoton ________________________________________________
Fazon ________________________________________________
Identify the element that each configuration is describing AND using the configuration to state the number of valence electrons for the element.
1s2 2s2 2p6 3s1 ____________________
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d6 ____________________
[Kf] 5s2 4d10 ____________________
[Z] 6s2 4f14 5d10 6p2 ____________________
[It] 7s2 5f14 6d4 ____________________
1s2 2s2 2p6 3s2 3p4 ____________________
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 ____________________
[Kf] 5s2 4d10 5p3 ____________________
[Z] 6s2 4f14 5d6 ____________________
[It] 7s2 5f11 ____________________
Determine which of the following electron configurations are not valid ground state configurations, and state why (what’s wrong):
1s2 2s2 2p6 3s2 3p6 4s2 4d10 4p5 ____________________
1s2 2s2 2p6 3s3 3d5 ____________________
[T] 7s2 5f8 ____________________
[Kf] 5s2 4d10 5p5 ____________________
[Z] ____________________
Determine which element is represented by the following EXCITED state electron configuration.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 5p6 ____________________
1s2 2s2 2p6 3s0 3p6 ____________________
[Kf] 5s2 4d10 5p3 ____________________
[Z] 6s0 4f14 5d6 ____________________
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 6s2 _______________

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Faq

Chemistry
Step-by-step answer
P Answered by Master
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarity * L
mol = 0.15 * 0.03 = 0.0045 mol
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarit
Chemistry
Step-by-step answer
P Answered by PhD
Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.
Chemistry
Step-by-step answer
P Answered by Specialist
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation:
A mechanical device using which we can change the direction or magnitude of force applied is known as simple machine.
For example, in the given diagram there are two individual simple machines.
The machine helps in changing the direction or magnitude of force applied by the man. As a result, it becomes easy for him to carry different things easily from one place to another.
Thus, we can conclude that the statement Fiona is correct because the diagram shows two individual simple machines, is correct.
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation
Chemistry
Step-by-step answer
P Answered by PhD

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry
Step-by-step answer
P Answered by PhD

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N ×328 K

Solving:

Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry
Step-by-step answer
P Answered by PhD
15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.
Chemistry
Step-by-step answer
P Answered by PhD
Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g
Chemistry
Step-by-step answer
P Answered by PhD
Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g
Chemistry
Step-by-step answer
P Answered by PhD
Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows (look at the picture)

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.
Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined a

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