29.01.2023

A transmission channel between two communicating DTEs is made up of three sections. The first introduces an attenuation of 16 dB, the second introduces an amplification of 20 dB, and the third introduces an attenuation of 10 dB. Assuming a mean transmitted power level of 400 mW, determine the mean output power level of the channel. (3 points)

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24.06.2023, solved by verified expert
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the mean output power level of the channel is 100.475 mW

Explanation:

Given the data in the question;

for the first section; attenuation

16 = 10log₁₀  400/P₂

P₂ = 10.0475 mW

For the second section;  amplification

20 = 10log₁₀  p₂/10.0475

p₂ = 1004.75 mW

For the third section; attenuation

10 = 10log₁₀  p₂/1004.75  

p₂ = 100.475 mW

i.e the mean output power level is 100.475 mW

or better still overall attenuation channel = ( 16 - 20) + 10 = 6dB

so

6 = 10log₁₀  400/P₂

p₂ = 100.475 mV

the mean output power level of the channel is 100.475 mW

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Engineering
Step-by-step answer
P Answered by PhD

the mean output power level of the channel is 100.475 mW

Explanation:

Given the data in the question;

for the first section; attenuation

16 = 10log₁₀  400/P₂

P₂ = 10.0475 mW

For the second section;  amplification

20 = 10log₁₀  p₂/10.0475

p₂ = 1004.75 mW

For the third section; attenuation

10 = 10log₁₀  p₂/1004.75  

p₂ = 100.475 mW

i.e the mean output power level is 100.475 mW

or better still overall attenuation channel = ( 16 - 20) + 10 = 6dB

so

6 = 10log₁₀  400/P₂

p₂ = 100.475 mV

the mean output power level of the channel is 100.475 mW

Engineering
Step-by-step answer
P Answered by Master

True, a retractable service pit cover can help other shop employees from falling into the pit while another technician is in the pit servicing a car.

Retractable service pit cover is a special cover made to cover service pit which aid inspection and repair of vehicle in an auto workshop.

Retractable service pit ensure safety of workshop technicians around service pits.Retractable service pits aid proper inspection of the beneath of the vehicleRetractable service pits enable the technician to have a close view of the vehicle in repair.The pit also serves as guide to short-eyed people or people to are not aware of the structure.In essence, the pit prevent against injury or death of workers and occupier.

In conclusion, the retractable service pit cover help other shop employees from falling into the pit even if they are aware of the structure.

Learn more about retractable service pit in picture attached

Engineering
Step-by-step answer
P Answered by PhD

Code:

#include <iostream>

using namespace std;

int main()

{

  int Car_Year;

  cout<<"Please Enter the Car Model."<<endl;

  cin>>Car_Year;    

 if (Car_Year<1967)

 {

cout<<"Few safety features."<<endl;

 }

else if (Car_Year>1971 && Car_Year<=1991)

{

cout<<"Probably has head rests."<<endl;

}

else if (Car_Year>1991 && Car_Year<=2000)

{

cout<<"Probably has antilock brakes."<<endl;

}

else if (Car_Year>2000)

{

cout<<"Probably has airbags."<<endl;

  }

else

{

cout<<"Invalid Selection."<<endl;

}

  return 0;

}

Output:

Please Enter the Car Model.

1975

Probably has head rests.

Please Enter the Car Model.

1999

Probably has antilock brakes.

Please Enter the Car Model.

2005

Probably has airbags.

Please Enter the Car Model.

1955

Few safety features.

Explanation:

We were required to implement multiple If else conditions to assign car model year with the corresponding features of the car.

The code is tested with a wide range of inputs and it returned the same results as it was asked in the question.

Engineering
Step-by-step answer
P Answered by Master

NTQ

Explanation:

The given sequence is

BHE : FLI : JPM

If is clear that, alphabets on first places are B, F, J. Difference between their place vales is 4.

B+4=F,F+4=J ; so alphabet on first place of next term of sequence is J+4=N.

Similarly, alphabets on second places are H, L, P. Difference between their place vales is 4.

H+4=L,L+4=P ; so alphabet on second place of next term of sequence is P+4=T.

Alphabets on third places are E, I, M. Difference between their place vales is 4.

E+4=I,I+4=M ; so alphabet on third place of next term of sequence is M+4=Q.

Therefore, the next term is NTQ.

Engineering
Step-by-step answer
P Answered by PhD

The following code or the program will be used

Explanation:

def readFile(filename):

   dict = {}

   with open(filename, 'r') as infile:

       lines = infile.readlines()

       for index in range(0, len(lines) - 1, 2):

           if lines[index].strip()=='':continue

           count = int(lines[index].strip())

           name = lines[index + 1].strip()

           if count in dict.keys():

               name_list = dict.get(count)

               name_list.append(name)

               name_list.sort()

           else:

               dict[count] = [name]

           print(count,name)

   return dict

def output_keys(dict, filename):

   with open(filename,'w+') as outfile:

       for key in sorted(dict.keys()):

           outfile.write('{}: {}\n'.format(key,';'.join(dict.get(key

           print('{}: {}\n'.format(key,';'.join(dict.get(key  

def output_titles(dict, filename):

   titles = []

   for title in dict.values():

       titles.extend(title)

   with open(filename,'w+') as outfile:

       for title in sorted(titles):

           outfile.write('{}\n'.format(title))

           print(title)

def main():

   filename = input('Enter input file name: ')

   dict = readFile(filename)

   if dict is None:

       print('Error: Invalid file name provided: {}'.format(filename))

       return

   print(dict)

   output_filename_1 ='output_keys.txt'

   output_filename_2 ='output_titles.txt'

   output_keys(dict,output_filename_1)

   output_titles(dict,output_filename_2)  

main()

Engineering
Step-by-step answer
P Answered by PhD

Energy equation from this week’s notes, your answer from #5, and Plank’s constant (6.63E-34) to find the approximate energy of this photon

Explanation:

1.The amount of energy in those photons is calculated by this equation, E = hf, where E is the energy of the photon in Joules; h is Planck's constant, which is always 6.63 * 10^-34 Joule seconds; and f is the frequency of the light in hertz

2.The first is Planck's equation, which was proposed by Max Planck to describe how energy is transferred in quanta or packets. Planck's equation makes it possible to understand blackbody radiation and the photoelectric effect. The equation is:

E = hν

where

E = energy

h = Planck's constant = 6.626 x 10-34 J·s

ν = frequency

Engineering
Step-by-step answer
P Answered by PhD

x=float(input("Enter a number: "))

sub=(x-int(x))

print(sub)

Explanation:

Got it Right

Engineering
Step-by-step answer
P Answered by Specialist

B ). When cleaning a vessel, use regular  household detergents and cleaners.

Explanation:

Boat cleaning or vessel cleaning is a tedious job. It takes a lot of hard work to clean a vessel. We have to be careful while maintaining the vessel.

The products that we use to clean and maintain the vessels needs to chosen carefully. Many boat cleaning products have adverse effects on the marine life and aquatic animals. it also tends to pollute the water bodies.

These products may be corrosive in nature, toxic or poisonous.

So we must use the regular household detergents and cleaners to clean our vessels. The regular detergents do not cause any harm to the nature and the water bodies.

We can use phosphate free no detergent soaps which may include citrus based soap or vegetable based soaps.

Therefore, while cleaning or maintaining vessels , use the regular household detergents and cleaners.  

Thus option (B) is correct.

Learn more :

link


Which statement regarding vessel maintenance is true?

When storing a vessel for a long time, it is
Engineering
Step-by-step answer
P Answered by Specialist

understanding others first before starting to explain your own point

Explanation:

Stephen covey believes the key to effective communication is understanding others first before starting to explain your own point. Communication is an important skill in life, in which one must have a good character in order to communicate effectively.

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