Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, −1), and S (1, −2). Russell and Jamie have both classified PQRS differently. Examine their proofs. Who is correct? Russell Jamie PQRS is a rhombus because all sides are congruent and opposite sides are parallel. Segment PQ P (0, 1) and Q (3, 2) Segment SR S (1, −2) and R (4, −1) Segment PS P (0, 1) and S (1, −2) Segment QR Q (3, 2) and R (4, −1) Segments PQ, QR, SR, and PS are all congruent. Segments PQ and SR are parallel, and segments PS and QR are parallel. PQRS is a square because all sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Segment PQ P (0, 1) and Q (3, 2) Segment SR S (1, −2) and R (4, −1) Segment PS P (0, 1) and S (1, −2) Segment QR Q (3, 2) and R (4, −1) Segments PQ, QR, SR, and PS are all congruent. Segments PQ and SR are parallel, and segments PS and QR are parallel. Segments PQ and QR are perpendicular, and segments PS and SR are perpendicular. Russell Jamie Both Neither Question 2(Multiple Choice Worth 1 points) (04.01 MC) Ivan used coordinate geometry to prove that quadrilateral EFGH is a square. Statement Reason 1. Quadrilateral EFGH is at E (−2, 3), F (1, 6), G (4, 3), and H (1, 0) 1. Given 2.__?__ 2. E (−2, 3) F (1, 6) F (1, 6) G (4, 3) G (4, 3) H (1, 0) E (−2, 3) H (1, 0) 3. 3. E (−2, 3) F (1, 6) G (4, 3) H (1, 0) 4. __?__ 4. E(−2, 3) H (1, 0) F (1, 6) G (4, 3) 5. and are perpendicular to 5. The slope of and is 1. The slope of is −1. 6. __?__ 6. The slope of and is −1. The slope of is 1. 7. Quadrilateral EFGH is a square 7. All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Which of the following completes statement 4 of the proof? , , , and are c