To solve this problem, we must recall that the formula for velocity assuming linear motion:
v = d / t
Where,
v = velocity
d = distance
t = time
For condition 1: bus travelling on a level road
v1 = d1 / t1
(v2 + 20) = (449 – d2) / 4 --->1
For condition 2: bus travelling on a winding road
v2 = d2 / t2
v2 = d2 / 5 --->2
Combining equations 1 and 2:
(d2 / 5) + 20 = (449 – d2) / 4
0.8 d2 + 80 = 449 – d2
1.8 d2 = 369
d2 = 205 miles
Using equation 2, find for v2:
v2 = 205 / 5
v2 = 41 mph
Since v1 = v2 + 20
v1 = 41 + 20
v1 = 61 mph
Therefore the average speed on the level road is 61 mph.
Bus speed: 22 mph; Trolley speed: 14 mph
Step-by-step explanation:
Let rb represent the speed of the bus and rt the speed of the trolley. Then rb = rt + 8 (mph).
Recall that distance = rate times time. Two different distances and two different speeds are involved here, but only one time.
Thus,
60 mi 44 mi
= time (same in both cases) =
rt + 8 mi/hr rt
Cross-multiplying, we get 44rt + 8(44) = 60 rt, or
352 = 16rt.
Solving this for rt, we get rt = speed of bus = 352/16 = 22 mph
The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph
Bus speed: 22 mph; Trolley speed: 14 mph
Step-by-step explanation:
Let rb represent the speed of the bus and rt the speed of the trolley. Then rb = rt + 8 (mph).
Recall that distance = rate times time. Two different distances and two different speeds are involved here, but only one time.
Thus,
60 mi 44 mi
= time (same in both cases) =
rt + 8 mi/hr rt
Cross-multiplying, we get 44rt + 8(44) = 60 rt, or
352 = 16rt.
Solving this for rt, we get rt = speed of bus = 352/16 = 22 mph
The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph
ANSWER AT THE BOTTOM BELOW
ANSWER AT THE BOTTOM BELOW
Firstly, there is an airplane flight.
1450 miles / 350mph = 4.14h
Secondly, there is a bus travel.
4.14h + 0.5h = 4.64h
The answer is C.
For every 8 cars there are 7 trucks
Therefore,
Cars:Truck=8:7
Answer is B)8:7
The answer is in the image
F=ma
where F=force
m=mass
a=acceleration
Here,
F=4300
a=3.3m/s2
m=F/a
=4300/3.3
=1303.03kg
Approximately it is aqual to 1300kg
It will provide an instant answer!