14.08.2020

The area of a blackboard is 1 1/3 square yards. A poster’s area is 8/9 square yards. Find the unit rate and explain, in words, what the unit rate means in the context of this problem. Is there more than one unit rate that can be calculated? How do you know?

. 33

Step-by-step answer

23.11.2022, solved by verified expert

Faq

Mathematics
Step-by-step answer
P Answered by Specialist

Unit rate of area of blackboard to area of poster = \frac{8}{33}

Unit rate of area of Poster to area of blackboard = = \frac{33}{8}              

Step-by-step explanation:

Rates help us to evaluate or compare two different quantities.

Unit rate help us to compare or know that how the  units of the quantity 1 is related to units of quantity 2.

We are given that:

Area of Blackboard = \frac{11}{3}

Area of Poster = \frac{8}{9}

Unit rate of area of blackboard to area of poster: It mean that how does unit area of blackboard is related to or corresponds to area of poster

= \frac{\text{Area of Poster}}{\text{Area of Blackboard}}= \frac{\frac{8}{9} }{\frac{11}{3} }

= \frac{8}{33}

Thus, 1 unit area of blackboard corresponds to \frac{8}{33}\text{ area of poster}

Unit rate of area of Poster to area of blackboard: It mean that how does unit area of poster is related to or corresponds to area of blackboard.

= \frac{\text{Area of Blackboard}}{\text{Area of Poster}}= \frac{\frac{11}{3} }{\frac{8}{9} }

= \frac{33}{8}

Thus, 1 unit area of Poster corresponds to \frac{33}{8}\text{ area of blackboard}

Mathematics
Step-by-step answer
P Answered by Master

Unit rate of area of blackboard to area of poster = \frac{8}{33}

Unit rate of area of Poster to area of blackboard = = \frac{33}{8}              

Step-by-step explanation:

Rates help us to evaluate or compare two different quantities.

Unit rate help us to compare or know that how the  units of the quantity 1 is related to units of quantity 2.

We are given that:

Area of Blackboard = \frac{11}{3}

Area of Poster = \frac{8}{9}

Unit rate of area of blackboard to area of poster: It mean that how does unit area of blackboard is related to or corresponds to area of poster

= \frac{\text{Area of Poster}}{\text{Area of Blackboard}}= \frac{\frac{8}{9} }{\frac{11}{3} }

= \frac{8}{33}

Thus, 1 unit area of blackboard corresponds to \frac{8}{33}\text{ area of poster}

Unit rate of area of Poster to area of blackboard: It mean that how does unit area of poster is related to or corresponds to area of blackboard.

= \frac{\text{Area of Blackboard}}{\text{Area of Poster}}= \frac{\frac{11}{3} }{\frac{8}{9} }

= \frac{33}{8}

Thus, 1 unit area of Poster corresponds to \frac{33}{8}\text{ area of blackboard}

Mathematics
Step-by-step answer
P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

Here,

tip=18%of $32

tip=(18/100)*32

=0.18*32

=$5.76

Total payment=32+5.76=$37.76

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