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02.02.2022

Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 EndFraction cups from the first orange, StartFraction 3 over 10 EndFraction cups from the second orange, StartFraction 9 over 20 EndFraction cups from the third orange, StartFraction 3 over 11 EndFraction cups from the fourth orange, and StartFraction 7 over 15 EndFraction cups from the fifth orange. Patel estimates that he needs 2 cups of orange juice for his family. About how much more orange juice does he need to reach his estimate? One-sixth cups Five-sixths cups 1 and two-thirds cups 1 and StartFraction 5 over 6 EndFraction cups

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Mathematics

Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 EndFraction cups from the first orange, StartFraction 3 over 10 EndFraction cups from the second orange, StartFraction 9 over 20 EndFraction cups from the third orange, StartFraction 3 over 11 EndFraction cups from the fourth orange, and StartFraction 7 over 15 EndFraction cups from the fifth orange. Patel estimates that he needs 2 cups of orange juice for his family. About how much more orange juice does he need to reach

Step-by-step answer

P Answered by PhD

3089/11220

Approximately = 0.2753

Step-by-step explanation:

Patel estimates that he needs 2 cups of Orange juice.

But let's know the amount he already has.

4/17 + 3/10 + 9/20 + 3/11 + 7/15

= 3/10 + 9/20 + 7/15 + 3/11 + 4/17

=( 18 + 27 + 28)/60 + (51+44)/187

= 73/60 + 95/187

=( 13651 + 5700)/11220

= 19351/11220

= 1(8131/11220)

So to complete it two he needs ( 11220-8131)/11220= 3089/11220

Approximately = 0.2753

Mathematics

Step-by-step answer

P Answered by PhD

$\approx \frac{11}{40}$

Step-by-step explanation:

Juice squeezed from first orange = $\frac{4}{17}$ = 0.235

Juice squeezed from second orange = $\frac{3}{10}$ = 0.3

Juice squeezed from third orange = $\frac{9}{20}$ = 0.45

Juice squeezed from fourth orange = $\frac{3}{11}$ = 0.27

Juice squeezed from fifth orange = $\frac{7}{15}$ = 0.47

Total juice squeezed from all the five oranges = 0.235 + 0.3 + 0.45 + 0.27 + 0.47 = 1.725

Total juice to be squeezed = 2 cups

More juice required = 2 - 1.725 = 0.275 $\approx \frac{11}{40}$

Therefore, to make it 2 cups of orange juice for the family, about $\approx \frac{11}{40}$ cups of more juice is required.

Mathematics

Step-by-step answer

P Answered by PhD

3089/11220

Approximately = 0.2753

Step-by-step explanation:

Patel estimates that he needs 2 cups of Orange juice.

But let's know the amount he already has.

4/17 + 3/10 + 9/20 + 3/11 + 7/15

= 3/10 + 9/20 + 7/15 + 3/11 + 4/17

=( 18 + 27 + 28)/60 + (51+44)/187

= 73/60 + 95/187

=( 13651 + 5700)/11220

= 19351/11220

= 1(8131/11220)

So to complete it two he needs ( 11220-8131)/11220= 3089/11220

Approximately = 0.2753

Mathematics

You can buy jars of the same jam in 2 sizes large jar:440g for £1.54 small jar:340g for £1.26 By considering the price per gram, work out which jar is the best value for money. Working must be shown

Step-by-step answer

P Answered by PhD

Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram

Mathematics

The last time Robert filled up his car with gas, he paid $24.50 for 7 gallons. This time, he needs 15 gallons. If the price is the same, how much will he pay?

Step-by-step answer

P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics

Anthony received $150 for his birthday this year. This was $10 less than half the amount he received last year. How much money did Anthony receive for his birthday last year?

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The answer is in the image

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A new school randomly assigns a six-character student code to every prospective student. The school uses the characters 1, 2, 3, 4, 5, X, Y, and Z. If none of the student codes contain a repeated character, what is the total number of codes that can be randomly assigned?

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P Answered by PhD

The total nom of code that can be used is equal to 5+3 = 8

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