Which angle is congruent to <cba

i think its a TwT

i might be wrong but i tried ;(

i think its a TwT

i might be wrong but i tried ;(

I would say ans is d because the angles are supplementary in this scenario

I see that as the only q

The correct option is;

(B) Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem.

Step-by-step explanation:

The given information are;

Lines AB and BC are parallel lines DC and AD respectively

AC constructed is congruent to AC (Reflexive property of equality)

∠BAC ≅ ∠DCA (Alternate angles theorem)

∠BCA ≅ ∠DAC (Alternate angles theorem)

Therefore, we have;

Triangle ΔBCA and triangle ΔDAC are congruent by Angle-Side-Angle (ASA) Theorem because, the congruent angles between ΔBCA and ΔDAC which are (∠BAC, ∠BCA in ΔBCA and ∠DCA and ∠DAC in ΔDAC) ∠BAC ≅ ∠DCA and ∠BCA ≅ ∠DAC are on opposite ends of the congruent line AC between the two triangles, therefore, we use the ASA Theorem

I would say ans is d because the angles are supplementary in this scenario

I see that as the only q

The correct option is;

(B) Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem.

Step-by-step explanation:

The given information are;

Lines AB and BC are parallel lines DC and AD respectively

AC constructed is congruent to AC (Reflexive property of equality)

∠BAC ≅ ∠DCA (Alternate angles theorem)

∠BCA ≅ ∠DAC (Alternate angles theorem)

Therefore, we have;

Triangle ΔBCA and triangle ΔDAC are congruent by Angle-Side-Angle (ASA) Theorem because, the congruent angles between ΔBCA and ΔDAC which are (∠BAC, ∠BCA in ΔBCA and ∠DCA and ∠DAC in ΔDAC) ∠BAC ≅ ∠DCA and ∠BCA ≅ ∠DAC are on opposite ends of the congruent line AC between the two triangles, therefore, we use the ASA Theorem

ΔAXC ~ ΔCXB

ΔACB ~ ΔAXC

Step-by-step explanation:

B and D are correct

ABC ~ EDF

Step-by-step explanation:

By the order of the letters, we can determine which triangles are similar.

We know that Angle D is congruent to Angle B. So we have to look for a set of triangles where D and B have the same place holders.

For example, if D is the first letter, then B also has to be the first letter.

The same thing applies for Angle E, and Angle A, since they are congruent to each other.

Wherever Angle E is, Angle A has to be in that same place holder.

Triangle ABC, has Angle B, as the second angle. Therefore we know the similar triangle has to be _D_.

Similarly, Angle A is congruent to Angle E, so we know that Angle E has to be in the first place holder. ED_

By process of elimination we know that the only corresponding angles left are C and F, they must be congruent. So the last thing to write is F.

Triangle ABC ~ Triangle EDF