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Option D : sinθ = a√(a²+2)/(a²+2)Step-by-step explanation:
Given,
Tanθ = perpendicular/base = a/√2
So Using Pythagoras theorem
Hypotenuse = √(a²+(√2)²)
= √(a²+2)
Therefore, sinθ = perpendicular/hypotenuse
= a/√(a²+2)
multiplying and dividing by √(a²+2)
sinθ = a/√(a²+2) × √(a²+2)/ √(a²+2)
sinθ = a√(a²+2)/(a²+2)
This, option D is correct.
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