14.06.2020

The weight (in kg) of cubical block of ice 75 cm in length (if one cubic metre of ice weight is 80 kg) is (1) 35

(2) 42.50

(3) 33.75

(4) 40

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Step-by-step answer

24.06.2023, solved by verified expert
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The weight = 33.75kg

Step-by-step explanation:

Given that  

one cubic metre of ice weight is 80 kg

which is mathematically written as

1m³ of ice = 80 kg

Therefore 75 cm length of  cubical  block of ice =???

First

changing  75 cm to meters, we have  75/100 = 0.75 m

Volume of block = l³= 0.75³ = 0.421875m³

Given that

1m³ = 80kg

0.421875m³=  0.421875 x 80

= 33.75kg

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Mathematics
Step-by-step answer
P Answered by PhD

The weight = 33.75kg

Step-by-step explanation:

Given that  

one cubic metre of ice weight is 80 kg

which is mathematically written as

1m³ of ice = 80 kg

Therefore 75 cm length of  cubical  block of ice =???

First

changing  75 cm to meters, we have  75/100 = 0.75 m

Volume of block = l³= 0.75³ = 0.421875m³

Given that

1m³ = 80kg

0.421875m³=  0.421875 x 80

= 33.75kg

Mathematics
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P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

The solution is given in the image below

The solution is given in the image below
Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

Mathematics
Step-by-step answer
P Answered by PhD

tip=18% of 75.45

     =18/100 * 75.45 = $13.581

Tip = $13.581

Mathematics
Step-by-step answer
P Answered by PhD

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years

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