14.06.2020

The weight (in kg) of cubical block of ice 75 cm in length (if one cubic metre of ice weight is 80 kg) is (1) 35

(2) 42.50

(3) 33.75

(4) 40

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Step-by-step answer

24.06.2023, solved by verified expert
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The weight = 33.75kg

Step-by-step explanation:

Given that  

one cubic metre of ice weight is 80 kg

which is mathematically written as

1m³ of ice = 80 kg

Therefore 75 cm length of  cubical  block of ice =???

First

changing  75 cm to meters, we have  75/100 = 0.75 m

Volume of block = l³= 0.75³ = 0.421875m³

Given that

1m³ = 80kg

0.421875m³=  0.421875 x 80

= 33.75kg

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Mathematics
Step-by-step answer
P Answered by PhD

The weight = 33.75kg

Step-by-step explanation:

Given that  

one cubic metre of ice weight is 80 kg

which is mathematically written as

1m³ of ice = 80 kg

Therefore 75 cm length of  cubical  block of ice =???

First

changing  75 cm to meters, we have  75/100 = 0.75 m

Volume of block = l³= 0.75³ = 0.421875m³

Given that

1m³ = 80kg

0.421875m³=  0.421875 x 80

= 33.75kg

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

Here,

tip=18%of $32

tip=(18/100)*32

=0.18*32

=$5.76

Total payment=32+5.76=$37.76

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

30% of 420 are first year students

first year students = (30/100 )*420

=126 students

Student who are not in first year = 420-126

=294 students  

Mathematics
Step-by-step answer
P Answered by PhD

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years

Mathematics
Step-by-step answer
P Answered by PhD

Given height of gymnasium is 5/6 height of 30 foot ball

therefore height of gymnasium=5/6 * 30

=25 feet

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