Write two numbers that multiply to 100 and add, №17886315, 01.12.2022 02:35

Mathematics

Write two numbers that multiply to 100 and add to 20

Step-by-step answer

P Answered by PhD

10*10

Step-by-step explanation:

Mathematics

Select all that apply. To write a percent as a decimal, . a. divide by 100 b. move the decimal point two places to the right c. move the decimal point two places to the left d. multiply by 100

Step-by-step answer

P Answered by PhD

2

A. Divide by 100

C. Move the decimal point two places to the left

Step-by-step explanation:

To write a percent as a decimal, divide by 100 or move the decimal point two places to the left.

Mathematics

Select all that apply. To write a percent as a decimal, . a. divide by 100 b. move the decimal point two places to the right c. move the decimal point two places to the left d. multiply by 100

Step-by-step answer

P Answered by PhD

2

A. Divide by 100

C. Move the decimal point two places to the left

Step-by-step explanation:

To write a percent as a decimal, divide by 100 or move the decimal point two places to the left.

Biology

55 points and i will mark brainliest if your answer actually using what you have learned, and the data provided for each trial, answer the questions in the essay box below. 1. imagine tossing a coin: what are your chances for tossing a head? what are your chances for tossing a tail? 2. a coin is tossed 10 times: how many times do you expect to get heads? how many times do you expect to get tails? 3. using this data for the 10 coin tosses, calculate and record the deviation observed from what you expected using the following formula: the more the

Step-by-step answer

P Answered by Specialist

4

Explanation:

1) 1/2 or 50% for both

2) 5/10 or 50% for both

3)7 heads 3 tails

4)50 heads and 50 tails I expect 50% head 50% tail

5) 50 of the tosses were heads while the other 50 was tails./

Biology

Okay need on this thing ughhh project: using what you have learned, and the data provided for each trial, answer the questions in the essay box below. imagine tossing a coin: what are your chances for tossing a head? what are your chances for tossing a tail? a coin is tossed 10 times: how many times do you expect to get heads? how many times do you expect to get tails? using this data for the 10 coin tosses, calculate and record the deviation observed from what you expected using the following formula: the more the experimental results deviate

Step-by-step answer

P Answered by Master

56

So basically two things:
1) you're going to have to flip the coins (or fake numbers) for the experimental trials.
2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.
When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.
|(100-50)| ÷ 50 = 50÷50 = 1.00
So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.
Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:
|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!
Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

History

Look at the change in population in Europe from 1300 to 1400, during the Black Death epidemic. Use a calculator to determine the percentage that the population declined between those two centuries. To get the answer, you need to subtract the population between the two centuries. Then, divide this difference in the population with the population in the year 1300. Finally, multiply by 100 to get the decline in percentage. Next, by using the same formula noted above, calculate the percentage that the population dropped in the Americas from 1500 to

Step-by-step answer

P Answered by Specialist

The population of Europe in 1300 was 70 million. The population dropped to 52 million in 1400.

The total decline in population was (70 – 52) = 18 million.

The decline in terms of percentage was

18/70 × 100 = 26% (approximately)

Similarly, the population of the Americas in 1500 was 42 million. The population in 1600 was 13 million.

The total decline in population (42 – 13) = 29 million

The decline in terms of percentage was

29/42 × 100 = 69% (approximately)

So, between the years 1300 and 1400, the population of Europe dropped by 26 percent. In the Americas, the population decline between 1500 and 1600 was 69 percent. So, the decline in population of the Americas between 1500 and 1600 was greater. Based on this fact, it seems likely that the spread of disease due to global trade had a much greater impact in the Americas than in Europe.

Explanation:

this is the sample answer directly from Edmentum! make sure you change it up a bit good luck!!

hope this helps :)

Mathematics

Select all that apply. to write a percent as a decimal, move the decimal point two places to the left multiply by 100 move the decimal point two places to the right divide by 100

Step-by-step answer

P Answered by PhD

2

Option A, move the decimal place two to the left

Option D, divide by 100

Step-by-step explanation:

Step 1: Find the answer

To write a percent as a decimal, divide by 100

To write a percent as a decimal, move the decimal place two to the left.

Example: Turn %56 into a decimal

56.0

0.56

Example: Turn %56 into a decimal

56 / 100

0.56

Option D, divide by 100

Biology

Someone please answer correctly and fully! I need help ASAP! 1. Imagine tossing a coin: What are your chances for tossing a head? What are your chances for tossing a tail? 2. A coin is tossed 10 times: How many times do you expect to get heads? How many times do you expect to get tails? 3. Using this data for the 10 coin tosses, calculate and record the deviation observed from what you expected using the formula for deviation The more the experimental results deviate from the expected results, the more the deviation value will approach the value

Step-by-step answer

P Answered by Master

2

These are a lot of questions, and I think once you have the basic understanding down you'll be able to answer the rest. I'll do a few to show you what to do though.

Explanation:

1. You have a coin. A coin is two sided, one with heads printed on it, one with tails printed on it. If you were to flip a coin- what would your chances be? Now if you have a coin that has heads on both sides the chances of flipping a heads is 100%. However, we have HALF of that- we have two different objects which would be 50%.

You have a 50% chance to flip a heads.

You have a 50% chance to flip a tails.

2. So if you flip the coin 10 times then- you would want it to try and be even. Since the data states we've flipped a coin twice and it's come out 50 50, we can assume it will be the same here.

Tails - 5 times

Heads - 5 times

I think you have the rest, best of luck ! Happy holidays and stay safe!

Mathematics

Select all that apply. to write a percent as a decimal, move the decimal point two places to the left multiply by 100 move the decimal point two places to the right divide by 100

Step-by-step answer

P Answered by PhD

7

Move the decimal point two places to the left

Divide by 100

Step-by-step explanation:

To write a percent as a decimal, there are two possible options, and they are the same thing.

The first one is moving the decimal point two places to the left. For example, 25% =0.25.

The second one is dividing by 100. 25% = 25/100 = 0.25.

So the answers are:

Move the decimal point two places to the left

Divide by 100

Biology

Okay need on this thing ughhh project: using what you have learned, and the data provided for each trial, answer the questions in the essay box below. imagine tossing a coin: what are your chances for tossing a head? what are your chances for tossing a tail? a coin is tossed 10 times: how many times do you expect to get heads? how many times do you expect to get tails? using this data for the 10 coin tosses, calculate and record the deviation observed from what you expected using the following formula: the more the experimental results deviate

Step-by-step answer

P Answered by Master

56

So basically two things:
1) you're going to have to flip the coins (or fake numbers) for the experimental trials.
2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.
When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.
|(100-50)| ÷ 50 = 50÷50 = 1.00
So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.
Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:
|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!
Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

Write two numbers that multiply to 100 and add to 20

Step-by-step answer

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