PLZ HELP PLZ HELP WHATS THE ANSWER Seven times, №17886937, 20.03.2023 18:32

Mathematics

PLZ HELP PLZ HELP WHATS THE ANSWER Seven times the first number plus six times the second number equals 31. - Three times the first number minus ten times the second number is 29. WHAT ARE THE TWO NUMBERS

Step-by-step answer

P Answered by PhD

For the first equation it should be 1 and 4 because 7(1)+6(4) would simplify to 7+24 which equals 31.

Then for the second equation, well... there’s multiple answers:

First would be 3 and -2 because 3(3)-10(-2) simplifies to 9+20=29.

Another one would be 23 and 4 because 3(23)-10(4) simplifies to 69-40=29.

Hopefully this helps :D

Mathematics

16. photon lighting company determines that the supply and demand functions for its most popular lamp are as follows: s(p) = 400 - 4p + 0.2p4 and d(p) = 2,800 - 0.0012p3, where p is the price. determine the price for which the supply equals the demand. a) $93.24 b) $100.24 c) $96.24 d) $99.24 17. write a polynomial function of minimum degree with real coefficients whose zeros include those listed. write the polynomial in standard form. 2, -4, and 1 + 3i (1 point) a) f(x) = x4 - 2x2 + 36x - 80 b) f(x) = x4 - 3x3 + 6x2 - 18x + 80 c) f(x) = x4 - 9x2

Step-by-step answer

P Answered by PhD

80

QUESTION 16

If the demand and supply are equal, then we equate the two functions in p and solve for p.

That is

S(p)=D(p)

$400 - 4p + + 0.00002 {p}^{4} = 2800 - 0.0012 {p}^{3}$

We can rearrange to obtain,

$0.00002 {x}^{4} + 0.0012 {x}^{3} - 4x - 2400 = 0$

$2 {p}^{2} + 1200 {p}^{3} - 400000p - 240000000 = 0$

The real roots of this polynomial equation are:

$p = - 118.26 \: p = 96.24$

Since price can not be negative, we discard the negative value ,

p = 96.24

The correct answer for question 16 is C.

QUESTION 17

We were given the solution to this polynomial as

x=2,x=-4, x=1+3i

We need to recognize the presence of the complex root and treat it nicely.

There is one property about complex roots of polynomial equations called the complex conjugate property. According to this property, if

a + bi

is a solution to

p(x)

then the complex conjugate

a - bi

is also a root.

Since

x = 1 + 3i

is a solution then,

x = 1 - 3i

is also a solution.

Therefore we have

f(x) = (x - 2)(x + 4)(x - (1+3i))(x - (1 - 3i)

$f(x) = ( {x}^{2} + 4x - 2x - 8)( {x}^{2} - (1 - 3i)x - (1 + 3i)x + (1 + 3i)(1 - 3i))$

We expand to obtain,

$( {x}^{2} + 4x - 2x - 8)( {x}^{2} - x + 3xi - x - 3xi + 1 + 9)$

Note that:

${i}^{2} = - 1$

$f(x) = ( {x}^{2} + 2x - 8)( {x}^{2} - 2x + 10)$

We now expand to obtain,

$f(x) = {x}^{4} - 2 {x}^{3} + 10 {x}^{2} + 2 {x}^{3} - 4 {x }^{2} + 20x - 8 {x}^{2} + 16x - 80$

We simplify further to obtain,

$f(x) = {x}^{4} + 2 {x}^{2} + 36x - 80$

The correct answer for question 17 is A.

QUESTION 18

If

-2i

is a zero of the polynomial,

f(x)=x^4-45x^2-196

then the complex conjugate

is also a zero,

This means that ,

(x+2i), (x-2i)

are factors of the polynomial.

The product of these two factors,

(x+2i), (x-2i) =x^2-(2i)^2=x^2+4

is also a factor , so we use it to divide and get the remaining factors.

see diagram for long division.

The above polynomial can therefore factored completely as,

f(x)=(x^2+4)(x^2-49)

Applying our knowledge from difference of two squares, we obtain,

f(x)=(x+2i)(x-2i))(x-7)(x+7)

Hence all the zeroes of these polynomial can be found by setting

(x+2i)(x-2i))(x-7)(x+7)=0

This implies,

x=-2i,x=2i,x=7,x=-7

The correct answer for question 18 is B

QUESTION 19

We were asked to find the horizontal and vertical asymptote of

$f(x)=\frac{2x^2+1}{x^2-1}$

To find the horizontal asymptote, divide the term with the highest degree in the numerator by the term with the highest degree in the denominators. That is the horizontal asymptote is given by,

$y=\frac{2x^2}{x^2}=2$

For vertical asymptote, equate the denominator to zero and solve for x.

x^2-1=

$\Rightarrow x=-1, x=1$

None of the options is correct, so the correct answer for question 19 is A.

QUESTION 20

We are converting,

$\frac{5\pi}{6}$

to degrees .

To convert from radians to degrees, multiply by,

$\frac{180\degree}{\pi}$

That is,

$\frac{5\pi}{6}=\frac{5\pi}{6} \times \frac{180\degree}{\pi}$

We simplify to obtain,

$\frac{5\pi}{6}=\frac{5}{1} \times \frac{180\degree}{1}=5\times30\degree =150\degree$

The correct answer is B.

QUESTION 21

Recall the mnemonics, SOH CAH TOA

The sine ratio is given by,

$\sin(B)=\frac{21}{75}=\frac{7}{25}$

From the diagram,

$\tan(B)=\frac{21}{72}=\frac{7}{24}$

The correct answer is C.

QUESTION 22

From the above diagram, We can determine the value of x using the sine or cosine ratio, depending on where the 17 is placed.

Using the cosine ratio, we obtain,

$\cos(58\degree)=\frac{17}{x}$

We can simply switch positions to make x the subject.

$x=\frac{17}{\cos(58\degree)}$

$x=\frac{17}{0.5299}$

x=32.08

Hence the correct answer is A.

QUESTION 23

Coterminal angles have the same terminal sides.

To find coterminal angles, we keep adding or subtracting 360 degrees.

See diagram.

$x=202\degree$

is coterminal with

$202\degree +360\degree =562\degree$

or

$202\degree -360\degree =-158\degree$

The correct answer is D.

See the attached file for continuation.

16. photon lighting company determines that the supply and demand functions for its most popular lam

Mathematics

16. photon lighting company determines that the supply and demand functions for its most popular lamp are as follows: s(p) = 400 - 4p + 0.2p4 and d(p) = 2,800 - 0.0012p3, where p is the price. determine the price for which the supply equals the demand. a) $93.24 b) $100.24 c) $96.24 d) $99.24 17. write a polynomial function of minimum degree with real coefficients whose zeros include those listed. write the polynomial in standard form. 2, -4, and 1 + 3i (1 point) a) f(x) = x4 - 2x2 + 36x - 80 b) f(x) = x4 - 3x3 + 6x2 - 18x + 80 c) f(x) = x4 - 9x2

Step-by-step answer

P Answered by PhD

80

QUESTION 16

If the demand and supply are equal, then we equate the two functions in p and solve for p.

That is

S(p)=D(p)

$400 - 4p + + 0.00002 {p}^{4} = 2800 - 0.0012 {p}^{3}$

We can rearrange to obtain,

$0.00002 {x}^{4} + 0.0012 {x}^{3} - 4x - 2400 = 0$

$2 {p}^{2} + 1200 {p}^{3} - 400000p - 240000000 = 0$

The real roots of this polynomial equation are:

$p = - 118.26 \: p = 96.24$

Since price can not be negative, we discard the negative value ,

p = 96.24

The correct answer for question 16 is C.

QUESTION 17

We were given the solution to this polynomial as

x=2,x=-4, x=1+3i

We need to recognize the presence of the complex root and treat it nicely.

There is one property about complex roots of polynomial equations called the complex conjugate property. According to this property, if

a + bi

is a solution to

p(x)

then the complex conjugate

a - bi

is also a root.

Since

x = 1 + 3i

is a solution then,

x = 1 - 3i

is also a solution.

Therefore we have

f(x) = (x - 2)(x + 4)(x - (1+3i))(x - (1 - 3i)

$f(x) = ( {x}^{2} + 4x - 2x - 8)( {x}^{2} - (1 - 3i)x - (1 + 3i)x + (1 + 3i)(1 - 3i))$

We expand to obtain,

$( {x}^{2} + 4x - 2x - 8)( {x}^{2} - x + 3xi - x - 3xi + 1 + 9)$

Note that:

${i}^{2} = - 1$

$f(x) = ( {x}^{2} + 2x - 8)( {x}^{2} - 2x + 10)$

We now expand to obtain,

$f(x) = {x}^{4} - 2 {x}^{3} + 10 {x}^{2} + 2 {x}^{3} - 4 {x }^{2} + 20x - 8 {x}^{2} + 16x - 80$

We simplify further to obtain,

$f(x) = {x}^{4} + 2 {x}^{2} + 36x - 80$

The correct answer for question 17 is A.

QUESTION 18

If

-2i

is a zero of the polynomial,

f(x)=x^4-45x^2-196

then the complex conjugate

is also a zero,

This means that ,

(x+2i), (x-2i)

are factors of the polynomial.

The product of these two factors,

(x+2i), (x-2i) =x^2-(2i)^2=x^2+4

is also a factor , so we use it to divide and get the remaining factors.

see diagram for long division.

The above polynomial can therefore factored completely as,

f(x)=(x^2+4)(x^2-49)

Applying our knowledge from difference of two squares, we obtain,

f(x)=(x+2i)(x-2i))(x-7)(x+7)

Hence all the zeroes of these polynomial can be found by setting

(x+2i)(x-2i))(x-7)(x+7)=0

This implies,

x=-2i,x=2i,x=7,x=-7

The correct answer for question 18 is B

QUESTION 19

We were asked to find the horizontal and vertical asymptote of

$f(x)=\frac{2x^2+1}{x^2-1}$

To find the horizontal asymptote, divide the term with the highest degree in the numerator by the term with the highest degree in the denominators. That is the horizontal asymptote is given by,

$y=\frac{2x^2}{x^2}=2$

For vertical asymptote, equate the denominator to zero and solve for x.

x^2-1=

$\Rightarrow x=-1, x=1$

None of the options is correct, so the correct answer for question 19 is A.

QUESTION 20

We are converting,

$\frac{5\pi}{6}$

to degrees .

To convert from radians to degrees, multiply by,

$\frac{180\degree}{\pi}$

That is,

$\frac{5\pi}{6}=\frac{5\pi}{6} \times \frac{180\degree}{\pi}$

We simplify to obtain,

$\frac{5\pi}{6}=\frac{5}{1} \times \frac{180\degree}{1}=5\times30\degree =150\degree$

The correct answer is B.

QUESTION 21

Recall the mnemonics, SOH CAH TOA

The sine ratio is given by,

$\sin(B)=\frac{21}{75}=\frac{7}{25}$

From the diagram,

$\tan(B)=\frac{21}{72}=\frac{7}{24}$

The correct answer is C.

QUESTION 22

From the above diagram, We can determine the value of x using the sine or cosine ratio, depending on where the 17 is placed.

Using the cosine ratio, we obtain,

$\cos(58\degree)=\frac{17}{x}$

We can simply switch positions to make x the subject.

$x=\frac{17}{\cos(58\degree)}$

$x=\frac{17}{0.5299}$

x=32.08

Hence the correct answer is A.

QUESTION 23

Coterminal angles have the same terminal sides.

To find coterminal angles, we keep adding or subtracting 360 degrees.

See diagram.

$x=202\degree$

is coterminal with

$202\degree +360\degree =562\degree$

or

$202\degree -360\degree =-158\degree$

The correct answer is D.

See the attached file for continuation.

Mathematics

7.03 1. write the sum using summation notation, assuming the suggested pattern continues. 1 - 3 + 9 - 27 + a) summation of one times three to the power of n from n equals zero to infinity b) summation of one times three to the power of the quantity n plus one from n equals zero to infinity c) summation of one times negative three to the power of n from n equals zero to infinity d) summation of one times negative three to the power of the quantity n plus one from n equals zero to infinity 2. write the sum using summation notation, assuming the suggested

Step-by-step answer

P Answered by PhD

42

This are 6 question and 6 answers

Problem 1. Write the sum using summation notation, assuming the suggested pattern continues.
1 - 3 + 9 - 27 + ...

option C) summation of one times negative three to the power of n from n equals zero to infinity

Explanation:

1) Sequence: 1 - 3 + 9 - 27: given

2) ratio of two consecutive terms:

- 3 / 1 = - 3

9 / (-3) = - 3

-27 / (9) = - 3

=> ratio = - 3 means that every term is the previous one multiplied by - 3

3) terms

First term: 1 * (-3)^0 = 1

Second term: 1* (-3)^1 = - 3

Third term: 1 * (-3)^2 = 9

Fourth term: 1 * (-3)^3 = - 27

So, the summation is:

∞
∑ 1 * (-3)^n ,
n=0

which is read summation of one times negative three to the power of n from n equals zero to infinity => option C.

Problem 2. Write the sum using summation notation, assuming the suggested pattern continues.

- 4 + 5 + 14 + 23 + ... + 131

option A) summation of the quantity negative four plus nine n from n equals zero to fifteen

Probe the statement A):

15
∑ (- 4 + 9n)
n=0

Now develop that summation: - 4 +9(0) - 4+ 9(1) - 4 + 9(2) - 4 + 9(3) ++ - 4 + 9(15) = - 4 + 5 + 14 + 23 + 131

Which is the very same sequence given.Therefore, the first statement if right.

Problem 3. Write the sum using summation notation, assuming the suggested pattern continues.
25 + 36 + 49 + 64 + ... + n^2 + ...

option A) summation of n squared from n equals five to infinity

Explanation

First term: 25 = 5^2
Second term: 36 = 6^2
Third term: 49 = 7^2
Fourth term: 64 = 8^2

nth term n^2

last term: the sequence is infinite

So, you can see that the sequence is the sum of the square of the integers from n = 5 to infinity =
∞
∑ (n^2)
n = 5

which is what summation of n squared from n equals five to infinity means.

Problem 4. Find the sum of the arithmetic sequence.
-1, 2, 5, 8, 11, 14, 17

option A) 56

Explanation:

You just have to sum all the terms (since they are few numbers that is the best way): - 1 + 2 + 5 + 8 + 11 + 14 + 17 = 56

56

Problem 5. Find the sum of the geometric sequence.
1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six

option D) 341 / 256

Explanation:
Write in form of fractions: 1 + 1/4 + 1/16 + 1/64 + 1/256

You'd better use the formula for the summation of a geometric sequence

k
∑ A * (r^n) = A * (1 - r^k) / (1 - r)
n=1

In this case: r = 1/4 (the ratio)
k = 5 (the number of terms)
A = 1 (the first term)

=> The sum = 1 * [1 - (1/4)^5 ] / [ 1 - 1/4], which when you simplify turns into 341 / 256 which is the option D.

Problem 6. Find the sum of the first 8 terms of the sequence. Show all work for full credit.
1, -3, -7, -11, ...

- 104

Explanation:

You can either sum the 8 terms or use the formula for the sum of an aritmetic sequence.

I will sum the 8 terms.

Note the the constant distance to sum is - 4, so the sum of the first eight terms is:

1 - 3 - 7 - 11 - 15 - 19 - 23 - 27 = - 104

Mathematics

7.03 1. write the sum using summation notation, assuming the suggested pattern continues. 1 - 3 + 9 - 27 + a) summation of one times three to the power of n from n equals zero to infinity b) summation of one times three to the power of the quantity n plus one from n equals zero to infinity c) summation of one times negative three to the power of n from n equals zero to infinity d) summation of one times negative three to the power of the quantity n plus one from n equals zero to infinity 2. write the sum using summation notation, assuming the suggested

Step-by-step answer

P Answered by PhD

42

This are 6 question and 6 answers

Problem 1. Write the sum using summation notation, assuming the suggested pattern continues.
1 - 3 + 9 - 27 + ...

option C) summation of one times negative three to the power of n from n equals zero to infinity

Explanation:

1) Sequence: 1 - 3 + 9 - 27: given

2) ratio of two consecutive terms:

- 3 / 1 = - 3

9 / (-3) = - 3

-27 / (9) = - 3

=> ratio = - 3 means that every term is the previous one multiplied by - 3

3) terms

First term: 1 * (-3)^0 = 1

Second term: 1* (-3)^1 = - 3

Third term: 1 * (-3)^2 = 9

Fourth term: 1 * (-3)^3 = - 27

So, the summation is:

∞
∑ 1 * (-3)^n ,
n=0

which is read summation of one times negative three to the power of n from n equals zero to infinity => option C.

Problem 2. Write the sum using summation notation, assuming the suggested pattern continues.

- 4 + 5 + 14 + 23 + ... + 131

option A) summation of the quantity negative four plus nine n from n equals zero to fifteen

Probe the statement A):

15
∑ (- 4 + 9n)
n=0

Now develop that summation: - 4 +9(0) - 4+ 9(1) - 4 + 9(2) - 4 + 9(3) ++ - 4 + 9(15) = - 4 + 5 + 14 + 23 + 131

Which is the very same sequence given.Therefore, the first statement if right.

Problem 3. Write the sum using summation notation, assuming the suggested pattern continues.
25 + 36 + 49 + 64 + ... + n^2 + ...

option A) summation of n squared from n equals five to infinity

Explanation

First term: 25 = 5^2
Second term: 36 = 6^2
Third term: 49 = 7^2
Fourth term: 64 = 8^2

nth term n^2

last term: the sequence is infinite

So, you can see that the sequence is the sum of the square of the integers from n = 5 to infinity =
∞
∑ (n^2)
n = 5

which is what summation of n squared from n equals five to infinity means.

Problem 4. Find the sum of the arithmetic sequence.
-1, 2, 5, 8, 11, 14, 17

option A) 56

Explanation:

You just have to sum all the terms (since they are few numbers that is the best way): - 1 + 2 + 5 + 8 + 11 + 14 + 17 = 56

56

Problem 5. Find the sum of the geometric sequence.
1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six

option D) 341 / 256

Explanation:
Write in form of fractions: 1 + 1/4 + 1/16 + 1/64 + 1/256

You'd better use the formula for the summation of a geometric sequence

k
∑ A * (r^n) = A * (1 - r^k) / (1 - r)
n=1

In this case: r = 1/4 (the ratio)
k = 5 (the number of terms)
A = 1 (the first term)

=> The sum = 1 * [1 - (1/4)^5 ] / [ 1 - 1/4], which when you simplify turns into 341 / 256 which is the option D.

Problem 6. Find the sum of the first 8 terms of the sequence. Show all work for full credit.
1, -3, -7, -11, ...

- 104

Explanation:

You can either sum the 8 terms or use the formula for the sum of an aritmetic sequence.

I will sum the 8 terms.

Note the the constant distance to sum is - 4, so the sum of the first eight terms is:

1 - 3 - 7 - 11 - 15 - 19 - 23 - 27 = - 104

Mathematics

The last time Robert filled up his car with gas, he paid $24.50 for 7 gallons. This time, he needs 15 gallons. If the price is the same, how much will he pay?

Step-by-step answer

P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics

An online media service offers video and music downloads. Each download of a song costs $1. Each download of a video costs 5 times as much as the song download. You have a credit of $70. How many songs can you purchase after buying 12 videos?

Step-by-step answer

P Answered by PhD