Solve for x. -3 < x - 10

x > 7

Step-by-step explanation:

-3 < x -10

=> x - 10 > -3

=> x > 10 - 3

=> x > 7

Answer B is correct

Step-by-step explanation:

hope this helps

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25

Step-by-step explanation:

Solve for x:

2 x - 50 = 0

Add 50 to both sides:

2 x + (50 - 50) = 50

50 - 50 = 0:

2 x = 50

Divide both sides of 2 x = 50 by 2:

(2 x)/2 = 50/2

2/2 = 1:

x = 50/2

The gcd of 50 and 2 is 2, so 50/2 = (2×25)/(2×1) = 2/2×25 = 25:

x = 25

25

Step-by-step explanation:

Solve for x:

2 x - 50 = 0

Add 50 to both sides:

2 x + (50 - 50) = 50

50 - 50 = 0:

2 x = 50

Divide both sides of 2 x = 50 by 2:

(2 x)/2 = 50/2

2/2 = 1:

x = 50/2

The gcd of 50 and 2 is 2, so 50/2 = (2×25)/(2×1) = 2/2×25 = 25:

x = 25

here u go gurly

Step-by-step explanation:

here u go gurly

Step-by-step explanation:

15.  Use the Rational Zeros Theorem to write a list of all potential rational zerosf(x) = x3 - 10x2 + 4x - 24

The constant term of () is -24

 The leading coefficient is 1.

We have to only consider the factors of the constant (leading coefficient = 1)

The factors are 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 24, -24

ANSWER TO QUESTION 1

We have the function

.

The domain of this function  refers to all -values for which is defined.

This is a rational function that is undefined whenever the denominator is equal to zero. As a result of this we need to exclude the x-values that will make the function undefined.

We can find these values by equating the the denominator to zero.

Also this rational function is undefined whenever the expression under the radical sign in the numerator is less than zero.

We must therefore restrict the expression under the square root sign in the numerator to be greater or equal to zero. Thus

Because of this last restriction, is eliminated from the restrictions.

Therefore the domain of is

,

The correct answer is C

ANSWER TO QUESTION 2

We have the function

which is a maximum function written in the vertex form.

It is a maximum function because when we compare to the general vertex form,

The vertex of the graph is .

The x-value of the vertex is

For , the graph is increasing and for the graph will be decreasing.

The correct answer is C

ANSWER TO QUESTION 3

and

The correct answer is C

ANSWER TO QUESTION 4

We have

The composition of the two functions

is given by;

This implies that;

The correct answer is B.

ANSWER TO QUESTION 5.

Given

.

Then

and

So that;

Which will give;

.

The correct answer is A

ANSWER TO QUESTION 6

The dimension of the smallest region are

km

and

If the length and width are increasing at the rate of  3km\sec, then after seconds, the dimensions will be,

km

and

km

This means the area after seconds is given by;

.

If the area is at least 4 times its original size, then we can write the inequality;

.

We expand to obtain;

We simplify to obtain,

We split factor to get;

This implies that;

or

Since we are dealing with time, we discard the negative value. Hence  it will   take

The correct answer is D.

ANSWER TO QUESTION 8

The correct answer is C.

This is how the following transformations affect the graph of

If , the graph opens down.

If , the graph opens up.

If , the graph graph shifts to the right b units.

If , the graph graph shifts to the left b units.

If , the graph graph shifts down c units.

If ,the graph graph shifts up c units.

Therefore for , the graph of moves to the right 14 units and moves down 9 units.

ANSWER TO QUESTION 9

The graph of

has y-intercept which is

and

has x-intercept which is

In order to transform the graph of in to , we need to shift  the x-intercept of the graph of f 14 units to the left.

The correct  answer is C

ANSWER TO QUESTION 10

The function;

.

This is a polynomial with a degree of 5 and the leading coefficient is .

The correct answer is C

ANSWER TO QUESTION 11

We have

We add and subtract half the coefficient of .

The first three term is a perfect square.

The correct answer is A.

ANSWER TO QUESTION 12

We want to solve;

To find the zeros of this function, we equate it to zero.

We factor to obtain;

We now split the middle term of the quadratic factor to get,

The correct answer is C.

See Attachment for the rest of the solutions

1) Find the domain of the given function.
f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two.

 using a graphical tool    see the attachment  

the answer is C) x ≥ -3, x ≠ 2  

 2. Identify intervals on which the function is increasing, decreasing, or constant.

g(x) = 2 - (x - 7)2

 using a graphical tool     

see the attachment

 the answer is  C) Increasing: x < 7; decreasing: x > 7

3. Perform the requested operation or operations.

f(x) = 4x + 7, g(x) = 3x2

Find (f + g)(x).

 (f + g)(x) = f(x) + g(x) 

(f + g)(x) = 4x + 7 + 3x^2 

(f + g)(x) = 3x^2 + 4x + 7

 The answer is  C) 4x + 7 + 3x2

 4. Perform the requested operation or operations.

f(x) = x minus five divided by eight. ; g(x) = 8x + 5, find g(f(x)).

 f(x)=(x-5)/8    g(x)=8x+5

g(f(x))=8((x-5)/8)+5=x-5+5=x

5. Find f(x) and g(x) so that the function can be described as y = f(g(x)).
y = nine divided by square root of quantity five x plus five. 

 y=f(g(x))=9/((5x+5) ^1/2)

let do

g(x)=5x+5...........so

f(x)= 9/( x^1/2)

6. A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle. As the camera zooms out, the length l and width w of the rectangle increase at a rate of 3 km/sec. How long does it take for the area A to be at least 4 times its original size?

Original size- >4km*4km=16 km2

4 times its original size---------------4*(16km2)-----64 Km2----------- > 8 km by 8 Km

Therefore

3km----------------------------- 1 sec

(8km-4km)---------------------x

X=4/3=1.33 sec

7. Find the inverse of the function.

f(x) = the cube root of quantity x divided by seven. - 9

to solve
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

f(x)=((x/7)-9) ^(1/3)

replace f(x) with y

y=((x/7)-9) ^(1/3)

switch x and y

x=((y/7)-9) ^(1/3)

solve for y

x^3=((y/7)-9)

x^3+9=y/7

y=7(x^3+9)

8. Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x - 14)2 – 9

9. Describe how to transform the graph of f into the graph of g. 
f(x) = alt='square root of quantity x minus nine.' and g(x) = alt='square root of quantity x plus five. '

f(x)=(x-9) ^1/2  g(x)=(x+5) ^1/2 

10. If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact.

f(x) = -16x5 - 7x4 – 6

11. Write the quadratic function in vertex form.
y = x2 + 4x + 7 

Complete the square on the right side of the equation

Use the form ax2+bx+cax2+bx+c, to find the values of a, b, and c.

a=1,b=4,c=7

Consider the vertex form of a parabola.

a(x+d)2+e

Find the value of dd using the formula d=b/2a

d=4/(2*1)=2

Find the value of e using the formula e=c−b2/4a

e=7−4=3

Substitute the values of a, d, and e into the vertex form a(x+d)2+e

(x+2)2+3

12. Find the zeros of the function.

f(x) = 3x3 - 12x2 - 15x

x1=-1

x2=0

x3=5

13. Find a cubic function with the given zeros.
7, -3, 2

X1=7

X2=-3

X3=2

f(x)=(x-7)(x+3)(x-2)=(x2-4x-21)(x-2)=x3-6x2-13x+42

14. Find the remainder when f(x) is divided by (x - k).
f(x) = 7x4 + 12x3 + 6x2 - 5x + 16; k = 3 

 f(x)=7(3)4+12(3)3+6(3)2-5(3)+16=946

15. Use the Rational Zeros Theorem to write a list of all potential rational zeros.
f(x) = x3 - 10x2 + 4x - 24

The constant term of

Percent error=(experimentally determined boiling point-actual boiling point)

                   =(124.1 - 125.7) = 1.6 °C

Quantity                   Number of significant figures

0.070020 meter                     5

10,800 meters                        5

0.010 square meter               2

5.00 cubic meters                  1

507 thumbtacks                     3

 (5.3 x 10⁴) + (1.3 x 10⁴) =6.6 x 10⁴

(7.2 x 10⁻⁴) ÷ (1.8 x 10³)=4 x 10⁻⁷

10⁴ x 10⁻³ x 10⁶=10⁷

(9.12 x 10⁻¹) - (4.7 x 10⁻²)=(9.12 x 10⁻²) - (4.7 x 10⁻²)

                                          =(91.2-4.7)  x 10⁻²

                                           =85.5 x 10⁻²