Mathematics : asked on QueensQueens

17.08.2022

Pick out the solution from the values given in bracket for the equation:
5 z +4 =24 (5, 4, 3,2)

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09.07.2023, solved by verified expert

Bibin (Bibi) P B

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The answer of this equation is 4. The following are the steps:

Pick out the solution from the values given in, №18009745, 17.08.2022 15:29

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Mathematics

Find the value of the variable which satisfies the equation by trying the values given in bracket: m/2= 5 (2 , 5 , 10 , 15)

Step-by-step answer

P Answered by PhD

m=10

m/2=5

m=2×5

m=10

so your answer is 10

Mathematics

Find the value of the variable which satisfies the equation by trying the values given in bracket: m/2= 5 (2 , 5 , 10 , 15)

Step-by-step answer

P Answered by PhD

m=10

m/2=5

m=2×5

m=10

so your answer is 10

Mathematics

Pick out the solution from the values given in bracket for the equation: 5 z +4 =24 (5, 4, 3,2)

Step-by-step answer

P Answered by Specialist

The answer of this equation is 4. The following are the steps:
Pick out the solution from the values given in bracket for the equation:
5 z +4 =24 (5, 4, 3,2)

Pick out the solution from the values given in bracket for the equation:
5 z +4 =24 (5, 4, 3,2)

Mathematics

Pick out the solution from the values given in the bracket.show that the other values do not satisfy the equation. 5t =35; ( 5, 7, 10, 12) pl solve

Step-by-step answer

P Answered by PhD

7

Step-by-step explanation:

5t = 35

t = 35 ÷ 5

t = 7

Mathematics

3x+9=8,(x= -1) check weather the value given in the bracket is a solution to the given equation or not

Step-by-step answer

P Answered by PhD

1

3(-1)+9=8
-3+9=8
6=8❌

So x= -1 is not a solution for the equation 3x+9=8

Mathematics

1) Check whether the value given in the bracket is a solution to the given equation or not. a) x + 7=12 ( x=5) b) 2x-3-10 (x=7).

Step-by-step answer

P Answered by PhD

yes and no

Step-by-step explanation:

Substitute the given values for x into the equationand if the value obtained is equal to the right side then it is a solution.

(a)

x + 7 = 5 + 7 = 12 ← True , thus x = 5 is a solution

(b)

2x - 3 = 2(7) - 3 = 14 - 3 = 11 ≠ 10, thus x = 7 is not a solution

Mathematics

3x+9=8,(x= -1) check weather the value given in the bracket is a solution to the given equation or not

Step-by-step answer

P Answered by PhD

1

3(-1)+9=8
-3+9=8
6=8❌

So x= -1 is not a solution for the equation 3x+9=8

Mathematics

1) Check whether the value given in the bracket is a solution to the given equation or not. a) x + 7=12 ( x=5) b) 2x-3-10 (x=7).

Step-by-step answer

P Answered by PhD

yes and no

Step-by-step explanation:

Substitute the given values for x into the equationand if the value obtained is equal to the right side then it is a solution.

(a)

x + 7 = 5 + 7 = 12 ← True , thus x = 5 is a solution

(b)

2x - 3 = 2(7) - 3 = 14 - 3 = 11 ≠ 10, thus x = 7 is not a solution

Mathematics

A. determine whether the mean value theorem applies to the following function on the given interval left bracket a comma b right bracket[a,b].b. if? so, find or approximate the? point(s) that are guaranteed to exist by the mean value theorem.c. make a sketch of the function and the line that passes through left parenthesis a comma f left parenthesis a right parenthesis right parenthesis(a,f(a)) and left parenthesis b comma f left parenthesis b right parenthesis right parenthesis(b,f( mark the points p? (if they? exist) at which the slope of the

Step-by-step answer

P Answered by PhD

f(x)=e^x is continuous and differentiable on its entire domain, so the mean value theorem holds for any interval you pick. We have

f'(x)=e^x

and the MVT says there is some $c\in(0,\ln15)$ such that

$f'(c)=\dfrac{f(\ln15)-f(0)}{\ln15-0}$

So we have

$e^c=\dfrac{15-1}{\ln15}=\dfrac{14}{\ln15}$

$\implies c=\ln\dfrac{14}{\ln15}\approx1.642$

A. determine whether the mean value theorem applies to the following function on the given interval

Mathematics

A. determine whether the mean value theorem applies to the following function on the given interval left bracket a comma b right bracket[a,b].b. if? so, find or approximate the? point(s) that are guaranteed to exist by the mean value theorem.c. make a sketch of the function and the line that passes through left parenthesis a comma f left parenthesis a right parenthesis right parenthesis(a,f(a)) and left parenthesis b comma f left parenthesis b right parenthesis right parenthesis(b,f( mark the points p? (if they? exist) at which the slope of the

Step-by-step answer

P Answered by PhD

f(x)=e^x is continuous and differentiable on its entire domain, so the mean value theorem holds for any interval you pick. We have

f'(x)=e^x

and the MVT says there is some $c\in(0,\ln15)$ such that

$f'(c)=\dfrac{f(\ln15)-f(0)}{\ln15-0}$

So we have

$e^c=\dfrac{15-1}{\ln15}=\dfrac{14}{\ln15}$

$\implies c=\ln\dfrac{14}{\ln15}\approx1.642$

A. determine whether the mean value theorem applies to the following function on the given interval

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