21.01.2023

Find the equation of the line from given point and slope a) passes through (-5,4) and has slope, m=1/2

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09.07.2023, solved by verified expert
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Slope-intercept form:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Standard form:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Step-by-step explanation:

Point-slope form of a linear equation: Find the equation of the line from given point, №18010742, 21.01.2023 08:13

(where Find the equation of the line from given point, №18010742, 21.01.2023 08:13 is the slope and Find the equation of the line from given point, №18010742, 21.01.2023 08:13 is the point)

Given:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Substituting these values into the point-slope formula:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Slope-intercept form:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

Standard form:

Find the equation of the line from given point, №18010742, 21.01.2023 08:13

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Mathematics
Step-by-step answer
P Answered by Master

Slope-intercept form:

y=\dfrac12x+\dfrac{13}2

Standard form:

x-2y=-13

Step-by-step explanation:

Point-slope form of a linear equation: y-y_1=m(x-x_1)

(where m is the slope and (x_1,y_1) is the point)

Given:

m=\dfrac12(x_1,y_1)=(-5,4)

Substituting these values into the point-slope formula:

\implies y-4=\dfrac12(x+5)

\implies y-4=\dfrac12x+\dfrac52

\implies y=\dfrac12x+\dfrac{13}2

Slope-intercept form:

y=\dfrac12x+\dfrac{13}2

Standard form:

x-2y=-13

Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

A:  slope-intercept form:  Solve 8y — 6x =8 for y, as follows:  8y = 6x + 8, so that y = (3/4)x + 1.

B:  Slope:  3/4; y-intercept:  (0, 1)

C:  Any line parallel to this line has the same slope, namely, 3/4.

D:  Any line perpendicular to this line has a slope that is the negative reciprocal of 3/4; that is, the slope of the perp. line is -4/3.

Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

A:  slope-intercept form:  Solve 8y — 6x =8 for y, as follows:  8y = 6x + 8, so that y = (3/4)x + 1.

B:  Slope:  3/4; y-intercept:  (0, 1)

C:  Any line parallel to this line has the same slope, namely, 3/4.

D:  Any line perpendicular to this line has a slope that is the negative reciprocal of 3/4; that is, the slope of the perp. line is -4/3.

Mathematics
Step-by-step answer
P Answered by Specialist
Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone

4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1

in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.

for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.

the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form

(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)

and lastly, plug in your given point: (1, 2)

y - 2 = (-2)(x - 1)

so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
Mathematics
Step-by-step answer
P Answered by Specialist
Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone

4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1

in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.

for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.

the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form

(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)

and lastly, plug in your given point: (1, 2)

y - 2 = (-2)(x - 1)

so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
Mathematics
Step-by-step answer
P Answered by PhD

1). Slope = \frac{3}{2}

2). Slope = \frac{2}{7}

3). Slope = -\frac{5}{9}

4). Option A. 2x + 4

5). Option C. \frac{2-0}{3-0}=\frac{6-2}{9-3}

Step-by-step explanation:

1). Slope of a line segment EF with E(-2, -4) and F(2, 2)

Slope m = \frac{-4-2}{-2-2}

m = \frac{-6}{-4}

m = \frac{3}{2}

2). Slope of a line segment AD with A(-3, -2) and D(4, 0)

Slope m = \frac{-2-0}{-3-4}

m = \frac{2}{7}

3). Slope of a line JK with J(-4, 2) and K(5, -3)

m = \frac{-3-2}{5+4}

m = -\frac{5}{9}

4). We have to determine the equation of the line given by graph.

In other words we have to determine the eequation of a line passing through (0, 4) and (-2, 0)

Equation will be in the form of y = mx + c

Where c = y-intercept = 4 units

Slope m = \frac{4-0}{0+2}=(2)

Therefore, equation of the line will be y = 2x + 4

Option A. 2x + 4 is the answer.

5). If triangles ABC and CFG are similar then AC and CG will have same slope.

Slope of AC with A(0,0) and C(3, 2) = Slope of CG with C(3, 2) and G(9, 6)

\frac{2-0}{3-0}=\frac{6-2}{9-3}

Therefore, Option C. is the correct option.

Mathematics
Step-by-step answer
P Answered by PhD

1). Slope = \frac{3}{2}

2). Slope = \frac{2}{7}

3). Slope = -\frac{5}{9}

4). Option A. 2x + 4

5). Option C. \frac{2-0}{3-0}=\frac{6-2}{9-3}

Step-by-step explanation:

1). Slope of a line segment EF with E(-2, -4) and F(2, 2)

Slope m = \frac{-4-2}{-2-2}

m = \frac{-6}{-4}

m = \frac{3}{2}

2). Slope of a line segment AD with A(-3, -2) and D(4, 0)

Slope m = \frac{-2-0}{-3-4}

m = \frac{2}{7}

3). Slope of a line JK with J(-4, 2) and K(5, -3)

m = \frac{-3-2}{5+4}

m = -\frac{5}{9}

4). We have to determine the equation of the line given by graph.

In other words we have to determine the eequation of a line passing through (0, 4) and (-2, 0)

Equation will be in the form of y = mx + c

Where c = y-intercept = 4 units

Slope m = \frac{4-0}{0+2}=(2)

Therefore, equation of the line will be y = 2x + 4

Option A. 2x + 4 is the answer.

5). If triangles ABC and CFG are similar then AC and CG will have same slope.

Slope of AC with A(0,0) and C(3, 2) = Slope of CG with C(3, 2) and G(9, 6)

\frac{2-0}{3-0}=\frac{6-2}{9-3}

Therefore, Option C. is the correct option.

Mathematics
Step-by-step answer
P Answered by PhD
Remark
This is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.

Question One
In the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid.  The graph is the left one for this question.

Question Two
Here I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.

Begin with the slope
Two lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2

Formula
m1 * m2 = - 1
4 * m2 = -1      Divide by 4
m2 = -1/4

So far what you have is
y = (-1/4)x + b

Now use the given point to solve for b
x = 5
y = - 1
b = ??

-1 = (-1/4)*5 + b
-1 = -5/4 + b  Add 5/4 to both sides
-1 + 5/4 + b   Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4

So the line that you want is
y = (-1/4) x + 1/4

Answers
One:  x = - 7
Two: y = (-1/4)x + 1/4

Note
The right graph is of y = 4x - 7 and y = (-1/4)x + 1/4
Write an equation in slope-intercept form for the line that passes through the given points and is (
Write an equation in slope-intercept form for the line that passes through the given points and is (
Mathematics
Step-by-step answer
P Answered by PhD
Remark
This is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.

Question One
In the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid.  The graph is the left one for this question.

Question Two
Here I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.

Begin with the slope
Two lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2

Formula
m1 * m2 = - 1
4 * m2 = -1      Divide by 4
m2 = -1/4

So far what you have is
y = (-1/4)x + b

Now use the given point to solve for b
x = 5
y = - 1
b = ??

-1 = (-1/4)*5 + b
-1 = -5/4 + b  Add 5/4 to both sides
-1 + 5/4 + b   Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4

So the line that you want is
y = (-1/4) x + 1/4

Answers
One:  x = - 7
Two: y = (-1/4)x + 1/4

Note
The right graph is of y = 4x - 7 and y = (-1/4)x + 1/4
Write an equation in slope-intercept form for the line that passes through the given points and is (
Write an equation in slope-intercept form for the line that passes through the given points and is (

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