9 MULTIPLY BY 1 OVER 4 PLS HELP ^_^, №18010816, 25.06.2020 00:54

Mathematics

9 MULTIPLY BY 1 OVER 4 PLS HELP ^_^

Step-by-step answer

P Answered by Master

Hi! I hope you're enjoying your day!

First, 9 times 1 is 9 (anything times 1 is itself)

Now, 9 over 4 is 9 divided by 4.

Is 9 divided by 4? Nope!

However, don't worry! The answer will be a fraction.

$\bold{\displaystyle\frac{9}{4}}$

Can this fraction be reduced? No.

Why? Because 9 and 4 have no common factors, except 1.

And if you divide by 1, nothing will change.

Hence, the answer is

Improper Fraction: $\boxed{\boxed{\bold{\displaystyle\frac{9}{4} }}}$

Mixed Number: $\boxed{\boxed{\bold{2\frac{1}{4} }}}$

Hope everything is clear.

If you have any questions, please comment.

#LearningIsFun

$\rule{250}{2}$

Mathematics

George jogged a total distance of 9 and 1 over 2 miles during the months of october and november. if george only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging? (5 points) 9 and 1 over 2 multiplied by 1 over 4 9 and 1 over 2 plus 1 over 4 9 and 1 over 2 divided by 1 over 4 9 and 1 over 2 minus 1 over 4 4. (02.01 hc) freddy has a shelf that is 72 over 5 inches wide. how many catalogs can freddy arrange on the shelf if each catalog is 4 over 5 of an inch thick? (5 points) 11, because the number

Step-by-step answer

P Answered by PhD

4

Part 1) 9 and 1 over 2 divided by 1 over 4

Part 2) 18, because the number of catalogs is 72 over 5 divided by 4 over 5

Part 3) 3.2

Part 4) 3.6 with bar over 6

Part 5) 4 over 7 and 4 over 9

Part 6) 43 over 9

Part 7) Benny spent to go to the summer camp $280.00

Part 8) $124

Part 9) (−$11) ⋅ 12

Part 10) -27 ft

Step-by-step explanation:

Part 1)

Let

x ------> the number of days

we now that

The total distance jogged must be equal to the distance jogged each day multiplied by the number of days

$9\frac{1}{2}=\frac{1}{4}x$

Solve for x

$x=\frac{9\frac{1}{2}}{\frac{1}{4}}$

therefore

The number of days is

9 and 1 over 2 divided by 1 over 4

Part 2)

Let

x ----> the number of catalogs

we know that

To find out the number of catalogs, divide the wide of the shelf by the thick of each catalog

$x=\frac{\frac{72}{5}}{\frac{4}{5}} =\frac{72}{4}= 18\ catalogs$

therefore

18, because the number of catalogs is 72 over 5 divided by 4 over 5

Part 3) Convert 16 over 5 to a decimal

we know that

$\frac{16}{5}=16(\frac{1}{5})=16(0.2) =3.2$

Part 4) How can 33 over 9 be expressed as a decimal?

we know that

$\frac{33}{9}= 3.666666...$ ----> is a repeating decimal

therefore

3.6 with bar over 6

Part 5) Which of the following numbers can be expressed as repeating decimals?

Verify each case

case a) 4 over 7

$\frac{4}{7}= 0.571428571428571428...$ ----> is a repeating decimal

case b) 2 over 5

$\frac{2}{5}=0.40$ ----> is a terminating decimal

case c) 7 over 8

$\frac{7}{8}=0.875$ ----> is a terminating decimal

case d) 4 over 9

$\frac{4}{9}=0.44444...$ ----> is a repeating decimal

therefore

4 over 7 and 4 over 9

Part 6) Which of the following rational numbers is equal to 4 point 7 with bar over 7 ?

Verify each case

case a) 43 over 9

$\frac{43}{9}= 4.77777...$

case b) 49 over 9

$\frac{49}{9}= 5.444444...$

case c) 35 over 9

$\frac{35}{9}= 3.888888...$

case d) 32 over 9

$\frac{32}{9}= 3.55555...$

therefore

43 over 9

Part 7)

we know that

1)Benny deposited $92.50 into his account every month for 10 month

so

$\$92.50(10)=\$925.00$

2) He used $36.50 every month to pay for art lessons

$\$925.00-10(\$36.50)=\$560.00$ -----> total money left in his account after 10 months

3) After 10 months, he used 1 over 2 of the total money left in his account to go to a summer camp for artists

so

$(1/2)(\$560)=\$280.00$

therefore

Benny spent to go to the summer camp $280.00

Part 8)

we know that

1) Mini earned $160 during the summer doing chores

2) She bought 3 dresses worth $12 each using her chore money.

so

$3(\$12)=\$36$

To find out how much money was left, subtract $36 from the amount earned during the summer doing chores

$\$160-\$36=\$124$

therefore

$124

Part 9)

we have

1 year=12 months

Let

x ----> the total deductions for the year

we know that

The total deductions for the year is equal to the Ryan's tennis club membership multiplied by the number of a months in a year

so

$x=(-\$11)12=-\$132$

therefore

(−$11) ⋅ 12

Part 10)

we know that

The total depth of a submarine is 45 ft

$15\%=15/100=0.15$

15% of 45 ft is

(0.15)(45)=6.75 ft

using proportion

Find out the deep after 4 minutes

Let

x ----> the deep after 4 minutes

$\frac{6.75}{1}\frac{ft}{min}=\frac{x}{4}\frac{ft}{min}\\\\x=6.75(4)\\\\x=27\ ft$

therefore

-27 ft

Mathematics

George jogged a total distance of 9 and 1 over 2 miles during the months of october and november. if george only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging? (5 points) 9 and 1 over 2 multiplied by 1 over 4 9 and 1 over 2 plus 1 over 4 9 and 1 over 2 divided by 1 over 4 9 and 1 over 2 minus 1 over 4 4. (02.01 hc) freddy has a shelf that is 72 over 5 inches wide. how many catalogs can freddy arrange on the shelf if each catalog is 4 over 5 of an inch thick? (5 points) 11, because the number

Step-by-step answer

P Answered by PhD

4

Part 1) 9 and 1 over 2 divided by 1 over 4

Part 2) 18, because the number of catalogs is 72 over 5 divided by 4 over 5

Part 3) 3.2

Part 4) 3.6 with bar over 6

Part 5) 4 over 7 and 4 over 9

Part 6) 43 over 9

Part 7) Benny spent to go to the summer camp $280.00

Part 8) $124

Part 9) (−$11) ⋅ 12

Part 10) -27 ft

Step-by-step explanation:

Part 1)

Let

x ------> the number of days

we now that

The total distance jogged must be equal to the distance jogged each day multiplied by the number of days

$9\frac{1}{2}=\frac{1}{4}x$

Solve for x

$x=\frac{9\frac{1}{2}}{\frac{1}{4}}$

therefore

The number of days is

9 and 1 over 2 divided by 1 over 4

Part 2)

Let

x ----> the number of catalogs

we know that

To find out the number of catalogs, divide the wide of the shelf by the thick of each catalog

$x=\frac{\frac{72}{5}}{\frac{4}{5}} =\frac{72}{4}= 18\ catalogs$

therefore

18, because the number of catalogs is 72 over 5 divided by 4 over 5

Part 3) Convert 16 over 5 to a decimal

we know that

$\frac{16}{5}=16(\frac{1}{5})=16(0.2) =3.2$

Part 4) How can 33 over 9 be expressed as a decimal?

we know that

$\frac{33}{9}= 3.666666...$ ----> is a repeating decimal

therefore

3.6 with bar over 6

Part 5) Which of the following numbers can be expressed as repeating decimals?

Verify each case

case a) 4 over 7

$\frac{4}{7}= 0.571428571428571428...$ ----> is a repeating decimal

case b) 2 over 5

$\frac{2}{5}=0.40$ ----> is a terminating decimal

case c) 7 over 8

$\frac{7}{8}=0.875$ ----> is a terminating decimal

case d) 4 over 9

$\frac{4}{9}=0.44444...$ ----> is a repeating decimal

therefore

4 over 7 and 4 over 9

Part 6) Which of the following rational numbers is equal to 4 point 7 with bar over 7 ?

Verify each case

case a) 43 over 9

$\frac{43}{9}= 4.77777...$

case b) 49 over 9

$\frac{49}{9}= 5.444444...$

case c) 35 over 9

$\frac{35}{9}= 3.888888...$

case d) 32 over 9

$\frac{32}{9}= 3.55555...$

therefore

43 over 9

Part 7)

we know that

1)Benny deposited $92.50 into his account every month for 10 month

so

$\$92.50(10)=\$925.00$

2) He used $36.50 every month to pay for art lessons

$\$925.00-10(\$36.50)=\$560.00$ -----> total money left in his account after 10 months

3) After 10 months, he used 1 over 2 of the total money left in his account to go to a summer camp for artists

so

$(1/2)(\$560)=\$280.00$

therefore

Benny spent to go to the summer camp $280.00

Part 8)

we know that

1) Mini earned $160 during the summer doing chores

2) She bought 3 dresses worth $12 each using her chore money.

so

$3(\$12)=\$36$

To find out how much money was left, subtract $36 from the amount earned during the summer doing chores

$\$160-\$36=\$124$

therefore

$124

Part 9)

we have

1 year=12 months

Let

x ----> the total deductions for the year

we know that

The total deductions for the year is equal to the Ryan's tennis club membership multiplied by the number of a months in a year

so

$x=(-\$11)12=-\$132$

therefore

(−$11) ⋅ 12

Part 10)

we know that

The total depth of a submarine is 45 ft

$15\%=15/100=0.15$

15% of 45 ft is

(0.15)(45)=6.75 ft

using proportion

Find out the deep after 4 minutes

Let

x ----> the deep after 4 minutes

$\frac{6.75}{1}\frac{ft}{min}=\frac{x}{4}\frac{ft}{min}\\\\x=6.75(4)\\\\x=27\ ft$

therefore

-27 ft

Mathematics

Step-by-step answer

P Answered by PhD

4

27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3

Step-by-step explanation:

Use of formula: (a^b)^c = a^(bc)

Solution

27^(1/3) =(3^3)^(1/3) =3^(3*1/3) =3

This is matching the last answer option

27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3

Mathematics

Which of the following shows the correct steps to find the value of 27 to the power of 1 over 3? a.)27 to the power of 1 over 3 equals 9 to the power of 3 to the power of 1 over 3 equals 9 to the power of 3 multiplied by 1 over 3 equals 9 b.)27 to the power of 1 over 3 equals 3 to the power of 9 to the power of 1 over 3 equals 3 to the power of 9 multiplied by 1 over 3 equals 3 c.)27 to the power of 1 over 3 equals 3 to the power of 4 to the power of 1 over 2 equals 3 to the power of 4 multiplied by 1 over 2 equals 9 d.)27 to the power of 1 over

Step-by-step answer

P Answered by PhD

41

27^1/3
=(3^3)^1/3
=(3^3)×1/3
=3, so your final answer is D.)27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3
Or
27^1/3=?
To find the answer, I will use one formula from Laws of Exponent
a^p/q
=q√a^p
Apply the same steps to 27^1/3
27^1/3
=³√27¹
=³√27
=3. Hope it help!

Mathematics

Which of the following shows the correct steps to find the value of 27 to the power of 1 over 3? a.)27 to the power of 1 over 3 equals 9 to the power of 3 to the power of 1 over 3 equals 9 to the power of 3 multiplied by 1 over 3 equals 9 b.)27 to the power of 1 over 3 equals 3 to the power of 9 to the power of 1 over 3 equals 3 to the power of 9 multiplied by 1 over 3 equals 3 c.)27 to the power of 1 over 3 equals 3 to the power of 4 to the power of 1 over 2 equals 3 to the power of 4 multiplied by 1 over 2 equals 9 d.)27 to the power of 1 over

Step-by-step answer

P Answered by PhD

41

27^1/3
=(3^3)^1/3
=(3^3)×1/3
=3, so your final answer is D.)27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3
Or
27^1/3=?
To find the answer, I will use one formula from Laws of Exponent
a^p/q
=q√a^p
Apply the same steps to 27^1/3
27^1/3
=³√27¹
=³√27
=3. Hope it help!

Mathematics

Step-by-step answer

P Answered by PhD

4

27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3

Step-by-step explanation:

Use of formula: (a^b)^c = a^(bc)

Solution

27^(1/3) =(3^3)^(1/3) =3^(3*1/3) =3

This is matching the last answer option

27 to the power of 1 over 3 equals 3 to the power of 3 to the power of 1 over 3 equals 3 to the power of 3 multiplied by 1 over 3 equals 3

Mathematics

George jogged a total distance of 9 and 1 over 2 miles during the months of october and november. if george only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging? 9 and 1 over 2 multiplied by 1 over 4 9 and 1 over 2 plus 1 over 4 9 and 1 over 2 divided by 1 over 4 9 and 1 over 2 minus 1 over 4

Step-by-step answer

P Answered by Specialist

27

Hello,

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

9 and 1 over 2 divided by 1 over 4

Mathematics

George jogged a total distance of 9 and 1 over 2 miles during the months of october and november. if george only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging? 9 and 1 over 2 multiplied by 1 over 4 9 and 1 over 2 plus 1 over 4 9 and 1 over 2 divided by 1 over 4 9 and 1 over 2 minus 1 over 4

Step-by-step answer

P Answered by Specialist

27

Hello,

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

9 and 1 over 2 divided by 1 over 4

Mathematics

George jogged a total distance of 9 and 1 over 2 miles during the months of october and november. if george only jogged 1 over 4 mile every day, which expression shows the number of days he went jogging? 9 and 1 over 2 multiplied by 1 over 4 9 and 1 over 2 plus 1 over 4 9 and 1 over 2 minus 1 over 4 9 and 1 over 2 divided by 1 over 4

Step-by-step answer

P Answered by PhD

4

1/4x = 9 1/2
x = (9 1/2) / (1/4)9 and 1/2 divided by 1 over 4 <===
x = (19/2) / (1/4)
x = 19/2 * 4
x = 76/2 = 38 days is how long he went jogging

9 MULTIPLY BY 1 OVER 4 PLS HELP ^_^

Step-by-step answer

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