Part A: The test average for the math class after completing 2 tests is 81
Part B: The test average for the science class after completing 2 tests is 83
Part C: The science class had the higher average test score after completing the test 4.
Step-by-step explanation:
The average test score for math class is given by the linear function, f(x) = 0.5·x + 80
The data for the average test score for science g(x) are;
x, q(x)
1, 81
2, 83
3, 85
Part A: The average test score for math after completing test 2 is given as follows;
f(2) = 0.5×2 + 80 = 81
∴ The test average for the math class after completing 2 tests = 81
Part B:
The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83
∴ The test average for the science class after completing 2 tests = 83
Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82
For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;
Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87
Since g(4) > f(4) the science class had the higher average test score after completing the test 4.
Science class had a higher average
Step-by-step explanation:
Given
g(x) table
Solving (a): f(2)
We have:
So:
Solving (b): g(2)
From the given table.
Solving (c): f(4) or g(4); which is greater
So:
For g(4): Notice that in the table of g(x); g(x) increases by 2 when x increases by 1
This means that:
So
Hence, g(4) i.e. Science class is greater
Science class had a higher average
Step-by-step explanation:
Given
g(x) table
Solving (a): f(2)
We have:
So:
Solving (b): g(2)
From the given table.
Solving (c): f(4) or g(4); which is greater
So:
For g(4): Notice that in the table of g(x); g(x) increases by 2 when x increases by 1
This means that:
So
Hence, g(4) i.e. Science class is greater
(a)
(b)
(c) Test average for maths class after test 2 is greater
Step-by-step explanation:
Given
Solving (a): f(2)
We have:
Solving (b): g(2)
From the table:
when
So:
Solving (c): Which is greater f(2) or g(2)
In (a) and (b),
Hence, test average for maths class is greater
SI=(P*R*T)/100
P=2000
R=1.5
T=6
SI=(2000*1.5*6)/100
=(2000*9)/100
=180
Neil will earn interest of 180
Cost of 7 gallons=$24.50
Cost of 1 gallon=24.50/7=3.5
Cost of 15 gallons=15*3.5=52.5
Cost of 15 gallons will be $52.5
The answer is in the image
y=2x+15
where y=Value of coin
x=Age in years
Value of coin after 19 years=2*19+15
=$53
Therefore, Value after 19 years=$53
F=ma
where F=force
m=mass
a=acceleration
Here,
F=4300
a=3.3m/s2
m=F/a
=4300/3.3
=1303.03kg
Approximately it is aqual to 1300kg
It will provide an instant answer!