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Chemistry : asked on bear342
 08.06.2021

How many moles of oxygen (O2) are required to react completely with 0.020 moles of aluminum (AI)

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Chemistry
The following balanced equation shows the formation of water. 2h2 + o2 → 2h2o how many moles of oxygen (o2) are required to react completely with 1.67 mol h2? a) 0.835 mol o2 b) 1.67 mol o2 c) 3.34 mol o2
Step-by-step answer
P Answered by PhD
Mole ratio of H₂  :  O₂   is   2  :  1

∴ if mole of H₂  =  1.67 mol

then mole of O₂ =  \frac{1.67 mol}{2}

⇒ that mole of oxygen needed to react with H₂  =  0.835 mol

The answer is A
Chemistry
The following balanced equation shows the formation of water. 2h2 + o2 → 2h2o how many moles of oxygen (o2) are required to react completely with 1.67 mol h2? 0.835 mol o2 1.67 mol o2 3.34 mol o2
Step-by-step answer
P Answered by Specialist

1) 0.835 mol O2

2) 1.47 mol H_{2}

Explanation:

just did it on edu

Chemistry
The following balanced equation shows the formation of water. 2h2 + o2 → 2h2o how many moles of oxygen (o2) are required to react completely with 1.67 mol h2? a) 0.835 mol o2 b) 1.67 mol o2 c) 3.34 mol o2
Step-by-step answer
P Answered by PhD
Mole ratio of H₂  :  O₂   is   2  :  1

∴ if mole of H₂  =  1.67 mol

then mole of O₂ =  \frac{1.67 mol}{2}

⇒ that mole of oxygen needed to react with H₂  =  0.835 mol

The answer is A
Chemistry
2h2 + o2 → 2h2o how many moles of oxygen (o2) are required to react completely with 1.67 mol h2?
Step-by-step answer
P Answered by Master
Mole ratio:

2 H2 + O2 =  2 H2O

2 mol H2 1 mol O2
1.67 mol H2 ??

1.67 x 1 / 2 => 0.835 moles of O2
Chemistry
2h2 + o2 → 2h2o how many moles of oxygen (o2) are required to react completely with 1.67 mol h2?
Step-by-step answer
P Answered by Master
Mole ratio:

2 H2 + O2 =  2 H2O

2 mol H2 1 mol O2
1.67 mol H2 ??

1.67 x 1 / 2 => 0.835 moles of O2
Chemistry
How many moles of oxygen (o2) are required to completely react with 27.4 mol of h2?
Step-by-step answer
P Answered by PhD
2 H₂ + O₂=  2 H₂O 

2 moles H₂ 1 mole O₂
27.4 moles H₂ ?

27.4 * 1 / 2 = 

=  27.4 / 2

= 13.7 moles of O₂

hope this helps!
Chemistry
The following balanced equation shows the formation of water. 2H2 + O2 2H2O How many moles of oxygen (O2) are required to completely react with 27.4 mol of H2
Step-by-step answer
P Answered by PhD

13.7 moles of O₂ are needed

Explanation:

In order to find the moles of reactants that may react to make the products we need to determine the reaction:

Reactants are hydrogen and oxygen

Product: Water

2 moles of hydrogen can react to 1 mol of oxygen and produce 2 moles of water.

Balanced reaction: 2H₂(g) + O₂(g) →  2H₂O(l)

If 2 moles of hydrogen need 1 mol of oxygen to react

Therefore, 27.4 moles of H₂ must need (27.4 .1) / 2 = 13.7 moles of O₂

Chemistry
2h2 + o2 2h2o how many moles of oxygen (o2) are required to completely react with 27.4 mol of h2? a.) 6.8 mol b.) 13.7 mol c.) 54.8 mol d.) 109.6 mol
Step-by-step answer
P Answered by PhD
2 H2 + O2 2 H2O

2 mol H2 1 mol O2
27.4 mol H2- x mol O2

2x  = 27.4

x = 27.4 / 2

x = 13.7 moles O2

answer b

hope this helps!.
Chemistry
2h2 + o2 mc020-1.jpg 2h2o how many moles of oxygen (o2) are required to completely react with 27.4 mol of h2? 6.8
Step-by-step answer
P Answered by Specialist

13.7 moles of oxygen (O₂) are required to completely react with 27.4 mol of H₂.

Explanation:

The complete question is:

"The following balanced equation shows the formation of water.

2H₂ + O₂ ----> 2H₂O

How many moles of oxygen (O₂) are required to completely react with 27.4 mol of H₂?

A: 6.8 mol

B: 13.7 mol

C: 54.8 mol

D: 109.6 mol"

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

So:

x=\frac{c*b}{a}

The rule of three can be applied in this case in the following way: by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), you know that 2 moles of H₂ react 1 mole of O₂. If there are 27.4 moles of H₂, how many moles of O₂ will react?

molesofO_{2} =\frac{27.4molesofH_{2}*1molefO_{2} }{2 molesofO_{2} }

moles of O₂=13.7

13.7 moles of oxygen (O₂) are required to completely react with 27.4 mol of H₂.

Chemistry
How many moles of oxygen (o2) are required to completely react with 27.4 mol of h2 equation: 2h2+ 2h20
Step-by-step answer
P Answered by Master
Balanced chemical equation

2 H2 + O2 = 2 H2O

2 moles H2 1 mole O2
27.4 moles H2 moles O2

moles O2 = 27.4 * 1 / 2

moles O2 = 27.4 / 2 => 13.7 moles
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